BIGFOOT (Readout)
ShalikaSingh - 15:22, Friday 20 September 2024 (3750)
Comment to RF circuit for EOM (Click here to view original report: 3745)

The Vpi, half wave voltage for the EOM is defined by the equation

V_{pi} = 0.361 * lambda - 23.844 = 0.361 * 1064 - 23.844 = 360.26 V (considering crystal with 14pF capacitane). The one we have says a capacitance of 12pF. 

(where lambda is in nm)

I tuned the circuit a bit more to obtain the gain of 7.397k with Moku supplying a 0.05V. So, with the updated circuit we will have

1. 0.05*7.397k = 369.8 V

2. Impedance of 48.9 ohm

3. OpAmp current of 11 mA.

4. Resonant frequency of 0.39MHz

I have updated the circuit diagram and transfer function.

PS: Moku can provide minimum of 1mVp-p using waveform generator function. 

Images attached to this comment
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